Re: Passing a reference to a std::map

From:
"Doug Harrison [MVP]" <dsh@mvps.org>
Newsgroups:
microsoft.public.vc.mfc
Date:
Tue, 24 Feb 2009 11:16:12 -0600
Message-ID:
<kka8q4drcai2uoetnmqe42osb8904rmkg6@4ax.com>
On Tue, 24 Feb 2009 17:48:46 +0100, "Bo Persson" <bop@gmb.dk> wrote:

Doug Harrison [MVP] wrote:

On Mon, 23 Feb 2009 16:36:28 -0800, jitter <jitter@jitter.com>
wrote:

For years, I have had the mistaken idea that passing a reference
would invoke a copy constructor.

Lesson learned!


References are not objects, and you can't "pass them". It's more
accurate to think in terms of "passing by reference" and "returning
by reference", and the implicit "what" in these phrases is
"objects". The association of a reference with an object is
immutable and called "binding". It is possible for a temporary
object to be created when an object of type X is bound to a const
reference of a different type Y; this will happen when X is
convertible to Y and isn't derived from Y. Otherwise, you're right,
and reference binding can be considered an almost free operation.
(Under the hood, references are typically implemented in terms of
pointers.)


You mean that pointers and references are both implemented in terms of
the address of the actual object? :-)


Sure, but references are at a higher level of abstraction and have
different usage rules. My parenthetical statement was intended to confirm
in a more concrete way the OP's conclusion that reference binding is cheap.

--
Doug Harrison
Visual C++ MVP

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