Re: when to call auto_ptr release?

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 19 Feb 2008 10:47:14 +0100
Message-ID:
<13rl9d5o76or7b8@corp.supernews.com>
* George:

Hello everyone,

Auto_ptr is convenient because of it saves our work and provides a framework
to auto-management life cycle to reduce potential resource leak.

But why do we sometimes need to call release method on auto_ptr to go back
to the style of manual management? Remember, when we call release, we need to
delete the object instance manually later.

(here is a sample I modified from MSDN auto_ptr sample code)

[Code]
// auto_ptr_release.cpp
// compile with: /EHsc
#include <memory>
#include <iostream>
#include <vector>
using namespace std;

class Int
{
public:
   Int( int i )
   {
      x = i;
      cout << "Constructing " << ( void* )this << " Value: " << x << endl;
   };
   ~Int( ) {
      cout << "Destructing " << ( void* )this << " Value: " << x << endl;
   };

   int x;

};

int main( )
{
   auto_ptr<Int> pi ( new Int( 5 ) );
   Int* pi3 = pi.release ();
   delete pi3;
}
[/Code]

thanks in advance,
George


This looks like obvious homework.

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