Re: FFEF behaviour

From:
rpv30@yahoo.co.in
Newsgroups:
microsoft.public.vc.language
Date:
12 Sep 2006 07:19:34 -0700
Message-ID:
<1158070773.886848.155290@d34g2000cwd.googlegroups.com>
Alex Blekhman wrote:

<rpv30@yahoo.co.in> wrote:

Consider the following piece of code:

void main()
{
   std::wstring testString;
   testString = 0xfeff;
   testString += L"123456";

   __int64 testI64;

   swscanf(testString.c_str(), L"%I64d", &testI64);
}

The swscanf() extracts the integer value from the string
in Windows
2000, but it fails in Windows 2003. Could anybody please
explain this
behaviour?


Are you trying to insert Unicode Byte Order Mark (BOM) into
string? BOM exists for files and other binary streams in
order to help stream consumer to determine byte order in the
stream. Using it within code is meaningless.


Actually, we are trying to read lines from a file and extract integers
from it. We are facing problems when we hit a BOM, which somehow has
crept into the file. I debugged the piece of code and traced the
failure to swscanf. So i wrote this program to simulate the scenario.

I understand that BOMs in the middle of the file need to be ignored,
but i just wanted to understand this behaviour.

Regards
Prasanna Venkatesh R

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