Re: Question about TCHAR string

From:

=?Utf-8?B?RGF2aWQrKw==?= <David@discussions.microsoft.com>

Newsgroups:

microsoft.public.vc.language

Date:

Wed, 18 Jul 2007 07:50:03 -0700

Message-ID:

<4E4B0ECC-1132-4489-B4E4-2F238310312B@microsoft.com>

"David Wilkinson" wrote:

David++ wrote:

Hi,

I've been spoiled with C# and the easy to use string functions. Now I'm into
a bit of C++ for writing a custom action for a DLL to be incorporated into an
MSI installer. Yikes.

What I'm basically doing is getting the Product Key from the
MsiGetProperty() function, like this -

TCHAR szPidKey[MAX_PATH];
DWORD dwPath;
dwPath = sizeof(szPidKey) / sizeof(TCHAR);

MsiGetProperty(hInstall, TEXT("PIDKEY"), szPidKey, &dwPath);

So I have my Product ID in szPidKey. Now I want to do some manual
verification of it. The Product ID is of the form -

123456789-ABCD-12

I need to verify this code so I need access to the beginning part
(123456789) and the end part (12). So I'm looking for a way to substring out
those parts of the string. I'm also looking to convert those substrings into
integer or long data type so i can do some checking on them, is it ok to use
itoa to do that?

Thanks very much for any hints.

David:

I think you meant atoi(). For TCHAR strings you should use _ttoi().
Generally, if you look up any 'char' function like atoi() in the MSDN
help, you will find the corresponding 'TCHAR' function also.

You could also do

typedef std::basic_istringstream<TCHAR> tistringstream;

if you like to use C++ streams.

--
David Wilkinson
Visual C++ MVP

Hi David,

Thanks for your quick response! Well spotted, indeed I meant atoi() ;-] I'll
have a browse over to those functions right away. They will probably be a lot
neater than my hand cooked attempt -

TCHAR szLicence[10] = {0};
TCHAR szSum[3] = {0};

for(int i=0; i<9; i++)
{
szLicence[i] = szPidKey[i];
szLicence[9] = '\0';
}

szSum[0] = szPidKey[15];
szSum[1] = szPidKey[16];
szSum[2] = '\0';

MessageBox(NULL, szLicence, TEXT("Key"), MB_OK);
MessageBox(NULL, szSum, TEXT("Key"), MB_OK);

Thanks again,
David