Re: How to get address of iterator currently pointer to?

From:
David Wilkinson <no-reply@effisols.com>
Newsgroups:
microsoft.public.vc.language
Date:
Wed, 08 Aug 2007 11:39:15 -0400
Message-ID:
<eE5o2Id2HHA.3764@TK2MSFTNGP04.phx.gbl>
Jack wrote:

"Jack" <jl@knight.com> ?????????g??????l??????s???D:Ob0Lusc2HHA.6128@TK2MSFTNGP02.phx.gbl...

Let's say I have an iterator "it"
std::string::iterator it;
char *__w64 startAddr = &it[0];
char *__w64 endAddr = startAddr + buf.size();
The start and end addresses tell me the start and end of file in memory

After it is incremented for a few times, I'd like to get the address of
the iterator currently pointing to?
The problem is if I compare "it" with another address, using the form
if (it <= endAddr)
      break the infinite loop

whoops
   if (it >= endAddr)
            break the loop

the compiler doesn't like it and throws C2678.
Does anyone know how to work around it?


Jack:

You are never going to get anywhere if you keep mixing these old C ways
with the C++ standard library. Get a book!!!

AFAIK, iterators do not define operator [], unless they happen to be
implemented as pointers (which they may or may not be).

Also, unlike std::vector, std::string is not guaranteed to be stored in
contiguous memory (although it probably always is).

std::string = "12345";
std::string::iterator itBegin = str.begin();
std::string::iterator itEnd = str.end();

for (std::string::iterator it = itBegin; it != itEnd; ++it)
{
   // stuff
}

--
David Wilkinson
Visual C++ MVP

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