Re: placement new called by vector<> during resizing.
On Apr 20, 3:04 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:
Anu wrote:
We have a class that has its own overloaded operator new and whose
prototype seems to correspond to the standard placement new :-
class AppClass
{
public:
operator new (size_t size, void *ctx)
.....
}
The ctx is important for us. Now we find that if we have a
vector<AppClass> instance, when the vector is resized, our overloaded
operator new is called!. Here is the comment from the STL vector
implementation :-
template<class _T1,
class _T2> inline
void _Construct(_T1 _FARQ *_Ptr, const _T2& _Val)
{ // construct object at _Ptr with value _Val
new ((void _FARQ *)_Ptr) _T1(_Val);
}
Is this documented somewhere in the standard?
No, it's an implementation detail.
Not really. The standard does require that the implementation
of vector separate allocation and construction, and the only way
to call a constructor is by using placement new.
I would consider this a bug in the library; the statement in
question should be:
::new ((void _FARQ *)_Ptr) _T1(_Val);
, since this is the only way to guarantee that you get the
standard placement new. I think a bug report is justified. (On
the other hand, I'm not really too surprised about the bug.
It's the sort of thing that's easy to overlook.)
--
James Kanze (Gabi Software) email: james.kanze@gmail.com
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