Re: STL destruction question...

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
21 Apr 2007 02:49:23 -0700
Message-ID:
<1177148962.932875.108560@y80g2000hsf.googlegroups.com>
On Apr 21, 2:30 am, "barcaroller" <barcarol...@music.net> wrote:

"Ian Collins" <ian-n...@hotmail.com> wrote in message

news:58t3hhF2i6eqtU23@mid.individual.net...

barcaroller wrote:

When a STL container is destroyed, will the destructor of the individu=

al

objects be automatically called?


Yes, assuming they have one!


(Formally, all objects have destructors. Some destructors are
trivial, however.)

Does this also apply to object pointers (e.g. set<Class*>)?


Of course. The pointer gets destroyed. (Of course, the
destructor of a pointer is trivial, so nothing much really
happens.)

The library does not persue pointers. Luckily, because in a lot
of cases, the set<Class*> is used for navigation, and there are
still a lot of other pointers to the objects when the set gets
destructed.

In this case I
would create the object myself (using 'new Class') but I assume that, sin=

ce

I created it, I should destroy it.


Correct.

However, there's no reason why the STL
container could not do that for me (by calling delete for each object).
Would it?


Only that it would break most common uses of sets of pointers.
It's really fairly rare for a container to have ownership of a
non-value object.

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