Re: best efficient and readable way to concatenate strings (or the
best trade-offs)
Diego Martins wrote:
Since C++ (and STL) have many ways to do string concatenation, I want
to hear (read) from you how you do to concatenate strings with other
strings and other types. The approaches I know are:
-- ostringstream
this does the job well, but:
* all types involved have to support operator<<
* we will lose some readibility in the code because we will always
have to create a temp object to do the concatenation
int n;
float x;
...
ostringstream temp;
temp << "we bought " << n << " items at " << x << " price";
notebook.add(temp.str());
// three liner :(
-- string::operator+
most advantage is we can built all the string using a one liner and
passing the result to string const &, but:
* we have to ensure all members are of string type
* to achieve that, we can use boost::lexical_cast or custom functions
to convert our types/classes to string
int n;
float x;
...
notebook.add("we bought " + toString(n) + " items at " + toString(x) +
" price");
// one liner!! :)
(but is there actually a gain doing that?)
and we have to implement toString(). which way is better?
lexical_cast? ostringstream? overloading (or specializing) for each
involved types? (ints and floats can be converted faster using some
hacks)
-- ostringstream wrapped in a (family) of functions
this technique combines the stream versatility with the oneliner
concatenation thing, but without RVO, I am not sure we will gain
anything:
int n;
float x;
...
notebook.add(concat("we bought ",n," items at ",x," price"));
// one liner!! :)
template<typename A, typename B, typename C, typename D>
string concat(A a, B b, C c, D d) {
ostringstream temp;
temp << a << b << c << d;
return temp.str();
}
this works, but one does not need to be a genius to figure out we have
to define a family of concat functions to handle the different number
of parameters
any ideas?
thanks!!!
Diego
HP
I'm a fan of classes like the following:
#include <sstream>
#include <string>
class concat
{
public:
template <typename T>
explicit concat(const T & t)
{
m_out << t ;
}
template <typename T>
concat & operator()(const T & t)
{
m_out << t ;
return *this ;
}
std::string str() const
{
return m_out.str() ;
}
private:
std::ostringstream m_out ;
} ;
#include <iostream>
int main()
{
int n = 4 ;
float x = .99 ;
std::string test = concat("We bought ")(n)(" items at ")(x)("
price").str() ;
std::cout << test << std::endl ;
}
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