Re: pointer to a member function?

From:
Barry <dhb2000@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 04 Oct 2007 10:22:13 +0800
Message-ID:
<fe1mdr$uta$1@news.cn99.com>
aaragon wrote:

On Oct 2, 8:57 pm, Barry <dhb2...@gmail.com> wrote:

aaragon wrote:

Hi everybody, I was wondering if there is an easy solution to this
problem in order to avoid writing some extra code:
I have a template class that has a member function called map:

DON'T have a name that is already used in standard library as your
identifier. I hardly can go on with your code.

template <class P>
class Q {
 typedef P::R RType;

dependent type,

typedef typename P::R RType;

  ...
  RType* map(P*, P*, int) {
     ... // do some stuff
   }
};
Now, in another function contained in class Q, I need to sort a vector
and for that I use a functor:
template <class P>
class SortFunctor {
    typedef typename P::R RType;
    P* p1_;
    P* p2_;
public:
    SortFunctor(P* p1, P* p2)
            : p1_(p1), p2_(p2) {}
    bool operator()(size_t left, size_t right) {
        return (map(left) < map(right));
    }
    RType* map(index) {

       RType* map(size_t index) {

        if (index < p1_->size())
            return p1_->rtype(index);
        else
            return p2_->rtype(index-p1_->size());
    }
};
So, this works perfectly, but I write the same function map in both

Already works? I think it does not even compile

the functor and in the template class Q. Now, I thought that it might
be cool to use a function to a pointer, so I added some extra stuff to
the functor so it looks like this (and of course I removed the
function map()):
template <class P>
class SortFunctor {
    typedef typename P::R RType;
    P* p1_;
    P* p2_;
    Rtype* (*map)(P*,P*,int);
public:
    SortFunctor(P* p1, P* p2, RType* fp)
            : p1_(p1), p2_(p2) { map = fp; }
...
};
and I have the following error message:
 error: ISO C++ forbids taking the address of an unqualified or
parenthesized non-static member function to form a pointer to member
function.

On the above, map is pointer to function, which is different from
pointer to member function.

I guess you write something like: &Klass::Fun, this is a pointer to
member function, its type is: ResultType (KlassType::*)(Arg1Type, Arg2Type);

If you have problem in pointer to member function, try to check it out
first.

Does anyone know how to do this? I appreciate any suggestions.
a?


Well, the code I wrote is not the actual code that I used, I
simplified it a lot to remove things that were not meaningful to the
problem. The function is not called map but decodeIndividual (but it
is basically a mapping, therefore the name that I chose for this
post). But still, what I'm asking is if what I'm trying to accomplish
is feasible or not. I read on the FAQ Lite and I found out that it is
very tricky to use pointers to member functions. They give a solution
giving a type definition, but of course that doesn't apply to my
problem because I deal with template classes and template functors.


View the code /binder1st/ /bind1st/ and /binder2nd/ /bind2nd/ in STL,
then you will know how to trait out the type of a pointer to member
function.

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