Re: std::max and NAN

From:
peter koch <peter.koch.larsen@gmail.com>
Newsgroups:
microsoft.public.vc.stl
Date:
Sat, 8 Dec 2007 09:23:18 -0800 (PST)
Message-ID:
<c12d3720-4324-4ede-a074-95afaeaedc15@r1g2000hsg.googlegroups.com>
On 26 Nov., 13:27, "Mycroft Holmes" <m.hol...@nospam.it> wrote:

"Ulrich Eckhardt" <eckha...@satorlaser.com> wrote in message

news:0koq15-qc6.ln1@satorlaser.homedns.org...

Mycroft Holmes wrote:

does the standard say anything about the behaviour of std::min/max does
on
(say, double) NAN?


I don't know the standard, but looking at the documentation for the STL,
it
mentions that '<' for max/min must provide a partial ordering, which
floating point numbers that are NAN simply break.


MSDN mentions that max/min return the first element if neither is
greater/lesser, but I don't know if that's standard.

I guess that you will find more such problems if you try to sort sequences
containing NAN.


well... not quite, that's more predictable, because a sorting algorithm
usually relies consistently on "less" and since all "less" return false,
NANs end up to the left (I'm speaking from a practical point of view -- as a
rule I totally agree with you).
Here you have an extra source of randomness: based on the result of an
(unknown) operator, you choose one argument or the other.


Sorry, but this is simply not correct. Calling std::sort with a
collection of doubles of which at least one is NaN causes undefined
behaviour and will in practice often have an unfortunate result such
as an infinite loop. If you want to have NaNs in your doubles, you
should provide your own comparison operator that makes the comparison
well-defined.

/Peter

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