Re: STL list Usage

From:
Greg Herlihy <greghe@mac.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 11 May 2008 20:30:27 -0700 (PDT)
Message-ID:
<115c84b1-01ef-4d39-bcdd-4945370b5519@u36g2000prf.googlegroups.com>
On May 11, 7:09 pm, mrc2...@cox.net (Mike Copeland) wrote:

   I am trying to learn/use the STL <list> to implement a small
application. I didn't get very far before I got a compile error that
befuddles me. Here's the code:

struct GENCHECK // Gender C=

heck data

{
  char genCode;
  string firstName;} gWork;

typedef list<GENCHECK> NAMES;
   NAMES genData;
   list<GENCHECK>::iterator gIter;

class nameEqual : public unary_function<NAMES, bool>
{ // predicate class to perform structure element comparison
        string s;
public:
  explicit nameEqual (const string &ss) : s(ss) {}
  bool operator() (const NAMES &e) const { return e.firstName == s; =

}

};


Instead of creating a "nameEqual" predicate, I would make it possible
to compare "GENCHECK" objects directly:

    struct GENCHECK // Gender Check data
    {
        char genCode;
        string firstName;

        bool operator==(const GENCHECK& rhs) const
        {
            return firstName == rhs.firstName;
        }

        bool operator<(const GENCHECK& rhs) const
        {
            return firstName < rhs.firstName;
        }

        bool operator==(const std::string& rhs) const
        {
            return firstName == rhs;
        }

        bool operator<(const std::string& rhs) const
        {
            return firstName < rhs;
        }
    } gWork;

With these operators defined, it is now possible to sort the list of
GENCHECK objects (by calling std::list.sort()) or to find a particular
object that matches a string (by calling std::find() on the list).

Greg

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