Re: pointer to a function?

From:

Victor Bazarov <v.Abazarov@comAcast.net>

Newsgroups:

comp.lang.c++

Date:

Wed, 18 Feb 2009 15:15:46 -0500

Message-ID:

<gnhq9j$2rp$1@news.datemas.de>

Fraser Ross wrote:

My example has code similar to this from Effective STL:
int g(double ());

The book says that the parameter double() is a pointer to a function.

Yes, and I have no problem.

According to the first thing you said Victor its a double value 0.

Well, that's not *exactly* what I said, Fraser. In that declaration, it
is a pointer. In the declaration

int g( ( double() ) );

it is NOT a function pointer, and instead a double value 0.

"It's a temporary object of type
S::RValue, default-constructed."

Yes. You had an extra set of parentheses *around* that text. It's a
different context. Please do not tear apart what I said. You cannot
take portions and twist them as you wish, you have to take the *entire*
story. All parts of it.

I can understand that you're frustrated with your buggy compiler. I
would be too. So, abstract for a minute from your woes and try to see
what Jeff and I have been telling you. Perhaps you need to re-read the
thread just once more...

V
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