Re: string allocation with '\0'

From:
Richard Herring <junk@[127.0.0.1]>
Newsgroups:
comp.lang.c++
Date:
Wed, 22 Jul 2009 11:06:32 +0100
Message-ID:
<dgTfVtDoSuZKFw7j@baesystems.com>
In message <7czlaxgkat.fsf@pbourguignon.anevia.com>, Pascal J.
Bourguignon <pjb@informatimago.com> writes

Pallav singh <singh.pallav@gmail.com> writes:

why should we do string allocation with '\0' in STL ? is it something
related to Backward compaitity to C ?


1- Nothing says that std::string uses '\0' to mark the end of the string.

2- "abc" is specified by C and for backward compatibility, by C++ to
  be and array of char containing 'a', 'b', 'c' and '\0'. This is
  necessary, since C++ didn't want to add a string basic type, or to
  map the "..." syntax to a call to std::string.

3- You don't have to use the C syntax "abc". You can write:
  std::string s; s.push_back('a'); s.push_back('b'); s.push_back('c');
// Look Ma! No '\0'!

4- You may write a pre-processor to expand any occurence of "abc" into:
   {static char temp[3]={'a','b','c'}; return std::string(temp,3);}


5- You may embed '\0' within std::string:
std::string s; s.push_back('a'); s.push_back('\0'); s.push_back('c');

--
Richard Herring

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