Re: Avoiding copying of an object

From:
Juha Nieminen <nospam@thanks.invalid>
Newsgroups:
comp.lang.c++
Date:
26 Sep 2010 09:52:03 GMT
Message-ID:
<4c9f17c3$0$14471$7b1e8fa0@news.nbl.fi>
Adam Markiewicz <amgo100@gmail.com> wrote:

I'm designing a container class similar to those in STL. It is implemented
as a template with two parameters: contained type and an allocator.

template <typename Type, typename Allocator>
class FixedArray


  Actually if you want it to be like the standard library containers, you
would have to make the allocator have a default value (so that the class
can be used without having to specify one explicitly), in other words:

template <typename Type, typename Allocator = std::allocator<Type> >
class FixedArray

Now, to write a function that takes FixedArray as a param to support
different allocators I would need (example):

template <typename Allocator>
float average(const FixedArray<float, Allocator>& array);

However array is const, so Allocator wouldn't be needed at all. Is would be
much simpler to write:

float average(const FixedArray<float>& array);


  If you want your function to support different types of 'FixedArray'
which use different allocators, the only way to do that is to make it
a template function where the allocator type is templatized, as you did
in the first example. That's because template classes with differing
template types are, effectually, completely different and independent
class types. It's like you had given them completely different names.

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