Re: std::make_shared creating a single block?

From:
SG <sgesemann@gmail.invalid>
Newsgroups:
comp.lang.c++
Date:
Thu, 22 Nov 2012 00:24:51 +0100
Message-ID:
<k8jnrv$iir$1@news.albasani.net>
Am 21.11.2012 23:59, schrieb Andy Champ:

I came across this reference:

<http://en.cppreference.com/w/cpp/memory/shared_ptr/make_shared>

"This function allocates memory for the T object and for the
shared_ptr's control block with a single memory allocation. In contrast,
the declaration std::shared_ptr<T> p(new T(Args...)) performs two memory
allocations, which may incur unnecessary overhead."


As Luca said, it's encounraged, not required.

The Microsoft compilers allocate two blocks for this, one for the
control block and one for the object.


Are you really sure? If I remember correctly, Stephan T. Lavavej -- one
of Microsoft's C++ standard library devlopers -- explained how this
one-allocation trick works in one of his pubpicly available lecture
videos [1]. So, I'm surprized to read that you think Microsoft
implements make_shared to use two memory allocations.

Cheers!
SG

[1]
<http://channel9.msdn.com/shows/Going+Deep/C9-Lectures-Stephan-T-Lavavej-Standard-Template-Library-STL-3-of-n/>

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