std::make_heap - compilation issues ?

From:
"Lady_A" <alexandra.lev@gmail.com>
Newsgroups:
microsoft.public.vc.language
Date:
31 Jan 2007 18:16:29 -0800
Message-ID:
<1170296189.915556.264850@h3g2000cwc.googlegroups.com>
Hi,

I have a set with a custom ordering operator defined on it.
My goal is get 10 max elements using another ordering.
To do that I am thinking to use make_heap algorithm on the set,
supplying the begin and end iterators of the set and a new ordering
operator.
The problem is that it wont compile, this is my code :
class A;
class B {
  class op1 {
    public:
      bool operator()(const A* const a,
                    A* const b) const { ...
     };
  };
class op2{
    public:
      bool operator()(const A* const a,
                    A* const b) const { ...
     };
  };
....
};

set<A*, op1>* my_set;
.....
void B:my_func() {
  make_heap(my_set->begin(), my_set()->end(), op2());
}

I also tried supplying the template params, i.e.
make_heap<set<A*, op1>::iterator, op2>(my_set->begin(), my_set()-

end(), op2());

In both cases I get the following error :

c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\algorithm(1150) :
 error C2784: 'reverse_iterator<_RanIt>::difference_type std::operator
-(const s
td::reverse_iterator<_RanIt> &,const std::reverse_iterator<_RanIt>
&)' : could n
ot deduce template argument for 'const std::reverse_iterator<_RanIt>
&' from 'st
d::set<_Kty,_Pr>::iterator'
        with
        [
            _Kty=A*,
            _Pr=B::op1
        ]
        c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\xutility(
634) : see declaration of 'std::operator`-''
        ../myfile.cc(825) : see reference to funct
ion template instantiation 'void
std::make_heap<std::set<_Kty,_Pr>::iterator,B::op2>(_RanIt,_RanIt,B::op2)'
being compiled
        with
        [
            _Kty=A*,
            _Pr=B::op1,
            _RanIt=std::set<A*,B::op1>::iterator
        ]
c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\algorithm(1150) :
 error C2784: 'reverse_iterator<_RanIt>::difference_type std::operator
-(const s
td::reverse_iterator<_RanIt> &,const std::reverse_iterator<_RanIt>
&)' : could n
ot deduce template argument for 'const std::reverse_iterator<_RanIt>
&' from 'st
d::set<_Kty,_Pr>::iterator'
        with
        [
            _Kty=A *,
            _Pr=B::op1
        ]
        c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\xutility(
634) : see declaration of 'std::operator`-''
c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\algorithm(1150) :
 error C2784: 'reverse_iterator<_RanIt>::difference_type std::operator
-(const s
td::reverse_iterator<_RanIt> &,const std::reverse_iterator<_RanIt>
&)' : could n
ot deduce template argument for 'const std::reverse_iterator<_RanIt>
&' from 'st
d::set<_Kty,_Pr>::iterator'
        with
        [
            _Kty=A*,
            _Pr=B::op1
        ]
        c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\xutility(
634) : see declaration of 'std::operator`-''
c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\algorithm(1150) :
 error C2784: 'reverse_iterator<_RanIt>::difference_type std::operator
-(const s
td::reverse_iterator<_RanIt> &,const std::reverse_iterator<_RanIt>
&)' : could n
ot deduce template argument for 'const std::reverse_iterator<_RanIt>
&' from 'st
d::set<_Kty,_Pr>::iterator'
        with
        [
            _Kty=A*,
            _Pr=B::op1
        ]
        c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\xutility(
634) : see declaration of 'std::operator`-''
c:/Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\algorithm(1150) :
 error C2676: binary '-' : 'std::set<_Kty,_Pr>::iterator' does not
define this o
perator or a conversion to a type acceptable to the predefined
operator
        with
        [
            _Kty=A*,
            _Pr=B::op1
        ]

Why do I need operator- ? Operator for comparing is not enough ?
It's hard to define such operator on A (thats what I need to define it
on, if I understand correctly), it would not have any logic.

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