Re: Using same port number to connect more than one application to

From:
Stephen Myers <""StephenMyers\"@discussions@microsoft.com">
Newsgroups:
microsoft.public.vc.mfc
Date:
Tue, 28 Apr 2009 09:38:21 -0500
Message-ID:
<ufve77AyJHA.4632@TK2MSFTNGP03.phx.gbl>
Joseph M. Newcomer wrote:

Not to mention an MSDN example of a chat server.

I keep wondering why everyone has this overwhelming urge to implement their own IM
mechanism. (Or FTP client, to cite another thread recently). There are plenty of
well-understood open-source examples of all of these that creating yet another chat server
(YACS) doesn't seem all that productive.

[Byt the way, I'm pretty sure I know what is wrong with the original code, but since it
wasn't presented, there's no point in giving an answer to a non-question]
                    joe

I wonder if it's a matter of realizing what's available and knowing the
magic search term(s) to get from 2 million useless hits to something
reasonable.

Steve

On Mon, 27 Apr 2009 08:41:08 -0500, Stephen Myers
<""StephenMyers\"@discussions@microsoft.com"> wrote:

nexolite wrote:

Please If anyone can reply fast , on whatever you think.

"nexolite" wrote:

Actually I want to build a application to handle connections from the chat
clients(which I have made).
Now since they are only clients so they need server to connect Now what I
want to accomplish is that:
1> Client X connects to the server(the program I am trying to build).

2> Client Y connects to the server.

3> Now there is a mapping with the server for X-Y so it will "connect" both
these.
means it will send the messages received from X to Y and from Y to X.
note that many such pairs will run simultaneously .

4> So now what is the best way to do this?

"Joseph M. Newcomer" wrote:

This code is neither interesting nor informative. You need to show YOUR code! You are
clearly triggering a valid error situation, but unless we see what you did, we have no way
to suggest how to fix it!

I have no idea what the nonsensical statement "everything works fine under Release build"
means, but what it almost certainly translates as is "my program is still broken in the
Release version, but it doesn't bother to tell me that it is malfunctioning because the
ASSERT statements are not compiled in Release versions". You have made the classic error,
thinking that absence of an error message means absence of an error. There's a *reason*
that the debug build fails: your program is wrong. The difference between debug and
release builds is that the release build doesn't bother to tell you that you screwed up.
NEVER play the "it works in Release mode" card until you have proven that it is not broken
in debug mode, and the ASSERT statement clearly tells you that your code is broken. The
"it works in release mode" rationale pretty much indicates that you haven't a clue that
your program really, truly, is broken. We sometimes call it the "ostrich approach" to bug
fixes (if I can't see the bug, it isn't there).

But since you simply duplicated a piece of code we all can see, without showing any of
your code (which is clearly wrong), we can't tell you how to fix it.
                joe

On Sat, 25 Apr 2009 06:21:01 -0700, nexolite <nexolite@discussions.microsoft.com> wrote:

I have a CAsyncSocket which listens on some port .if a single connection is
made to it everything is fine ,now if one more Client attempts to connects
then the following Assertion fails

in sockcore.cpp

BOOL CAsyncSocket::Accept(CAsyncSocket& rConnectedSocket,
    SOCKADDR* lpSockAddr, int* lpSockAddrLen)
{
    ASSERT(rConnectedSocket.m_hSocket == INVALID_SOCKET);
      ....
}

Although everything works fine under Release build but I want to know is
that a concern?

Joseph M. Newcomer [MVP]
email: newcomer@flounder.com
Web: http://www.flounder.com
MVP Tips: http://www.flounder.com/mvp_tips.htm


This seems to be a standard TCP Client/Server application.

Each connection to the server generates a new socket in OnAccept().
This is the new suggested by Scott. This newly created socket will NOT
use the known port that your server listens on. Each connection gets
its own socket from the server.

Take a careful look at the documentation. There are some reasonable
articles about what you'lll need to do.

Steve

Joseph M. Newcomer [MVP]
email: newcomer@flounder.com
Web: http://www.flounder.com
MVP Tips: http://www.flounder.com/mvp_tips.htm

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