Re: Hard to visualize this statement
Jacky wrote:
"Igor Tandetnik" <itandetnik@mvps.org>
???g???l???s?D:%23BQ%233$6QHHA.4692@TK2MSFTNGP05.phx.gbl...
"Jacky" <jl@knight.com> wrote in message
news:%23wOzM56QHHA.996@TK2MSFTNGP02.phx.gbl
Thanks for your reply. But I want to see some code in action (some
practical examples)
#include <queue>
#include <complex>
#include <iostream>
using namespace std;
int main() {
queue<complex<double> > q;
for (int n = 0; n < 10; ++n) {
q.push(complex<double>(n, n));
}
while (!q.empty()) {
cout << q.front() << endl;
q.pop();
}
return 0;
}
Dear Igor,
Let me interpret the snippet you wrote. Please don't mind if I got
that wrong
You first push two 2 integers into the complex<double> (I don't
understand why you don't have
to allocate memory to this complex list).
We in C++ use the term "construct a temporary 'complex<double>' by
means if the two-argument constructor. The two integers are converted
into 'doubles' before being passed to the constructor. You don't need
to allocate memory for temporary objects, it is done by C++ magic.
Then you push the whole
package to the queue
and poping back out. Thanks
No, he's pushing ten of those into the queue. Then he pops *all* of
them out, one by one.
V
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