Re: Returning Char array/pointer? Continuing of thread I am confused with these concepts.

From:
rockdale <rockdale.green@gmail.com>
Newsgroups:
microsoft.public.vc.language
Date:
Mon, 11 Feb 2008 13:38:22 -0800 (PST)
Message-ID:
<eff3cffe-2ce6-4628-a12d-8894a10287fd@i12g2000prf.googlegroups.com>
Thanks, I will try with your suggestion.

On Feb 11, 4:34 pm, "Ben Voigt [C++ MVP]" <r...@nospam.nospam> wrote:

rockdale wrote:

This is my function using std::string

std::string ReadFile2String(char const* aSrcFile){
ifstream in;
std::string strRtn;


Remove that line. C++ variables are declared at the point of constructi=

on,

not the top of the function.

long lngFileSize = 0;

in.open(aSrcFile, ios::in| ios::binary | ios::ate);
if(in.is_open()||in.bad())
{
lngFileSize = in.tellg();
}else{
throw exception("could not open input file"); // could not open in
file
return NULL;
}

char* chrTmp = new char[lngFileSize];
in.seekg(0,ios::beg);
in.read(chrTmp, lngFileSize);

strRtn = chrTmp; ???????


replace with

std::string(chrTmp, lngFileSize);
delete [] lngFileSize;

return strRtn;

}


But it would be better to use std::vector... and get rid of the explicit
allocation and extra copy.- Hide quoted text -

- Show quoted text -

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