Re: Returning Char array/pointer? Continuing of thread I am confused with these concepts.

Thanks for the reply.

I still have one thing:

2. Whne you pass by reference, you are indeed calling malloc (or new)
on the
original pointer (that is what pass by reference does for you).

By say that, did you mean I do not need to call delete in the caller?
Or did you mean I do not need to do the new inside my function?

        aDestArr = new char[lngFileSize+1];

--------------------
//Calling the func
char* myByte;
long lngSize = 0;

lngSize = readFileToByteArray("myFileName", myByte);

//Do I need to delete myByte here?

---------------------
my function

long ReadFileToByteArray(char const* aSrcFile, char* aDestArr){
        long lngFileSize = 0;
        int intBeenRead = 0;
        ifstream in;

        in.open(aSrcFile, ios::in| ios::binary | ios::ate);
        if(in.is_open()||in.bad())
        {
                lngFileSize = in.tellg();
        }else{
                throw exception("could not open input file"); // could
not open in
file
                return 0;
        }

        aDestArr = new char[lngFileSize+1];
        in.seekg(0,ios::beg);
        in.read(aDestArr, lngFileSize);
        aDestArr[lngFileSize] = '\0';
        in.close();
        return lngFileSize;

}