Re: array of zero elements

On Feb 17, 3:26 pm, George <Geo...@discussions.microsoft.com> wrote:


It is valid so that you can have code like this:

void f(size_t n)
{
     int * ptr = new int[n];
     //...
     delete[] ptr;
}

instead of:

void f(size_t n)
{
   if (n>0)
   {
     int * ptr = new int[n];
     //...
     delete[] ptr;
   }
}

No other use though, because since it has zero elements, you cannot
do anything with it.

That would not mean that there is no use of zero sized (or better
say 'unsized') arrays. VC++ has an extension which makes use of
zero sized arrays as the last member of structures. For example,
see this:

#include<cstdlib>
#include<iostream>
struct test
{
   int cb;
   int buf[];
};

int main()
{
   test* bb;
   int length = 10;
   bb = (test*) malloc(sizeof(test)+sizeof(int)*length);
   bb->cb = length;
   //fill buf with length int items or can copy from another array
for length elements
   bb->buf[i]=10; //i should be less than length
   //OR--------
   test aa = {10, {1,10,22,32}};
   std::cout << aa.buf[2];
}