Question about heritance and other aspects.

Question
1.--------------------------------------------------------------------------------------------------------------------------------------------

#include <iostream>
using namespace std;

class B
{
public:
    int i;

    B()
    {}
};

class A
{
public:
    A(B& b1)
    {
        b1.i=0;
    }
};

class C : public A
{
    B b;
public:
    C() : A(b)
    {}
};

As the code above, b is a private object for class C. Why I can revise b as
a reference in constructor of class A.
As I know, even class C herites from class A, A can not revise any private
properties in C, is that right?

Question
2.--------------------------------------------------------------------------------------------------------------------------------------------

class A
{
public:
    A()
    {}

    friend ostream& operator << (ostream& os,A& ac)
    {}
};

If I remove keyword "friend", operator << will be seen as a bit operator
instead of a stream operator, why? (I think If I add keyword "friend" before
the function
declaration, it just means this function can revise private properties in
class A, the keyword can not effect whether "<<" is a bit operator or not.)

Question
3.--------------------------------------------------------------------------------------------------------------------------------------------

Sorry,I write ASM in C++ newsgroup, but it's related with my question.

Coorder STRUCT
    X WORD ?
    Y WORD ?
Coorder ENDS

m_order Coorder <0,0>

It's about storage space in C++ thinking from assembly language (IA 32
instruction set)

ASM "STRUCT" itself(I mean declaration) will not be stored in storage space,
but for ASM "STRUCT Variant"(m_order) it will live in storage space at
runtime. (I don't know whether it's right.)

this description let me think about "class" in C++. Can I say: the
declaration of a "class" will not be stored in storage space? if what I said
is right, how C++ compiler deals with inline function
if "class" is not in storage space.

Thank you for your help.