Re: Hard to visualize this statement

From:

"Victor Bazarov" <v.Abazarov@comAcast.net>

Newsgroups:

microsoft.public.vc.language

Date:

Mon, 29 Jan 2007 10:35:18 -0500

Message-ID:

<epl47n$2u7$1@news.datemas.de>

Jacky wrote:

"Igor Tandetnik" <itandetnik@mvps.org>
???g???l???s?D:%23BQ%233$6QHHA.4692@TK2MSFTNGP05.phx.gbl...

"Jacky" <jl@knight.com> wrote in message
news:%23wOzM56QHHA.996@TK2MSFTNGP02.phx.gbl

Thanks for your reply. But I want to see some code in action (some
practical examples)

#include <queue>
#include <complex>
#include <iostream>
using namespace std;

int main() {
   queue<complex<double> > q;

   for (int n = 0; n < 10; ++n) {
       q.push(complex<double>(n, n));
   }

   while (!q.empty()) {
       cout << q.front() << endl;
       q.pop();
   }

   return 0;
}

Dear Igor,
Let me interpret the snippet you wrote. Please don't mind if I got
that wrong
You first push two 2 integers into the complex<double> (I don't
understand why you don't have
to allocate memory to this complex list).

We in C++ use the term "construct a temporary 'complex<double>' by
means if the two-argument constructor. The two integers are converted
into 'doubles' before being passed to the constructor. You don't need
to allocate memory for temporary objects, it is done by C++ magic.

Then you push the whole
package to the queue
and poping back out. Thanks

No, he's pushing ten of those into the queue. Then he pops *all* of
them out, one by one.

V
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