Re: How come a 20MB file becomes a 50KB Memory object?

From:
"Igor Tandetnik" <itandetnik@mvps.org>
Newsgroups:
microsoft.public.vc.language
Date:
Sat, 11 Aug 2007 18:33:55 -0400
Message-ID:
<uUNq$gG3HHA.5740@TK2MSFTNGP04.phx.gbl>
"Jack" <jl@knight.com> wrote in message
news:%23EJvb2B3HHA.5360@TK2MSFTNGP03.phx.gbl

void process_file(std::string filename)
{
 long count = 0;
char c;

ifstream infile(filename.c_str ());


Try

ifstream infile(filename.c_str (), ios_base::in | ios_base::binary);

I have checked the path, it opened correctly. But It is a 20MB file,
how come this procedure tells me the loaded file only 50K?


My guess is, you have a binary file that just happens to contain a byte
with the value 26. Such a byte is interpreted as end-of-file indicator
when the file is read in text mode.

Not directly related to your problem, but you have chosen the most
inefficient way possible to read a file into memory. Consider using
memory-mapped files - see CreateFileMapping, MapViewOfFile et al.
--
With best wishes,
    Igor Tandetnik

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