Re: value_type of vector

From:
"Igor Tandetnik" <itandetnik@mvps.org>
Newsgroups:
microsoft.public.vc.language
Date:
Sun, 18 Nov 2007 23:08:20 -0500
Message-ID:
<uOwDUHmKIHA.6108@TK2MSFTNGP03.phx.gbl>
"George" <George@discussions.microsoft.com> wrote in message
news:1FCD6EDE-1B4B-413C-9359-79B5A528B984@microsoft.com

I think the value_type of vector<int> should be int and the
value_type of vector<int> should be int*.


In the second example you meant vector<int*>, right?

But I am not 100% sure


Why? If you don't trust the documentation, you can just look at the
source code.

1. how to write a program to verify this idea;


#include <iostream>
using namespace std;

int main() {
    cout << typeid(vector<int>::value_type).name() << endl;
    cout << typeid(vector<int*>::value_type).name() << endl;
    return 0;
}

2. where to find the definition that the value_type of interator of
vector<int> is int*.


What exactly is "value_type of interator"? I'm not sure what you are
talking about here.

int main (int argc, char** argv)
{
vector<int>::value_type; // should be int ?


Yes.

vector<int>::iterator::value_type; // should be int* ?


It doesn't even have to compile. vector<int>::iterator doesn't have to
provide value_type typedef. It doesn't even have to be a class type.
--
With best wishes,
    Igor Tandetnik

With sufficient thrust, pigs fly just fine. However, this is not
necessarily a good idea. It is hard to be sure where they are going to
land, and it could be dangerous sitting under them as they fly
overhead. -- RFC 1925

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