Re: Calling virtual method of base class nested in template class (VC++ 6.0)

From:
"Roger" <someone@idontwantspam.com>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 29 Aug 2006 13:46:29 GMT
Message-ID:
<VyXIg.1372$Cq4.316@newssvr25.news.prodigy.net>
Actually, I came up with a simpler example that exhibits the same bug (no
template, and nesting at only a single level):

#include <iostream>

class B
{

public:

  B( ) { }

  class N1
  {

  public:

    N1( ) { };

    virtual void f( )
    {
      std::cout << "B< >::N1::f( )" << std::endl;
    }

  };

};

class D : public B
{

public:

  class N1 : public B::N1
  {

  public:

    N1( ) : B::N1( ) { };

    virtual void f( )
    {
      typedef B::N1 BN1;

      std::cout << "D::N1::f( )" << std::endl;
      BN1::f( );
    }

  };

};

void
main( int argc, char* argv[ ] )
{
  D::N1 n1;

  n1.f( );
}

However, the problem is worked around by changing the name of D::N1 to
something other than N1. Apperently, the VC6.0 compiler becomes confused as
to which N1 I was referring and just assumed the most derived N1, rather
than the one specified by the typedef (i.e., the N1 in B).

When I renamed N1 to, say, Joe, it worked.

"Roger" <someone@idontwantspam.com> wrote in message
news:KNWIg.4215$yO7.3921@newssvr14.news.prodigy.com...

Hi all.

Here's a little quandry I've run in to and can't tell if it's a compiler
bug, or if it's bad code. First, here's the code:

===================================
#include <stdio.h>

template < typename T >
class B
{

public:

 B( ) { }

 class N1
 {

 public:

   N1( ) { };

   class N2
   {

   public:

     N2( ) { };

     virtual void f( )
     {
       printf( " B< >::N1::N2::f( )\n" );
     }

   };

 };

 T _m;

};

class D : public B< int >
{

public:

 class N1 : public B< int >::N1
 {

 public:

   N1( ) : B< int >::N1( ) { };

   class N2 : public B< int >::N1::N2
   {

   public:

     N2( ) : B< int >::N1::N2( ) { };

     virtual void f( )
     {
       typedef B< int >::N1::N2 Bint; // must do this to avoid VC6.0's
"error C2352: 'B<int>::N1::N2::f' : illegal call of non-static member
function" bug.

       printf( " D::N1::N2::f( )\n" );

       // B< int >::N1::N2::f( ) causes the compiler to complain (see
typedef above). However, VC7.1 works fine.
       Bint::f( );
     }

   };

 };

};

void
main( int argc, char* argv[ ] )
{
 D::N1::N2 n2;

 n2.f( );
}

==================================

Invoking n2.f( ) causes an infinite loop, dumping out "D::N1::N2::f( )"
ad-nausium. I am trying to call the base-class f( ) in B::N1::N2, but the
VC6.0
compiler just generates code that instead calls D::N1::N2::f( )
recursively.

VC7.1 compiles this just fine (even on the commented out line).

What am I doning wrong? Or, is this a compiler bug?
If it's a bug, is there a fix or how can I call the base's f( )?

BTW: I'm stuck w/VC6.0, so please don't suggest using VC7.1; thanks.

Thanks for any help you can offer!

- Roger

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