Re: Can you specialize the Template operator==

From:
3DCoderGuy <nobody@nospam.com>
Newsgroups:
microsoft.public.vc.language
Date:
Fri, 09 May 2008 09:40:01 -0700
Message-ID:
<uzx8UNfsIHA.524@TK2MSFTNGP05.phx.gbl>
3DCoderGuy wrote:

I'm trying to specialize the operator== for my template, here is my code

#define DOUBLE_EPSILON (1e-6)
#define FLOAT_EPSILON (1e-4f)

bool const operator==(const XYZPoint<T> &xyzTest) const
{
 return (
  (x == xyzTest.x) &&
  (y == xyzTest.y) &&
  (z == xyzTest.z)
  );
};

template<typename T>
 bool const operator==(const XYZPoint<float> &xyzTest) const
{
 return (
  (x - xyzTest.x < FLOAT_EPSILON) && (x - xyzTest.x > -FLOAT_EPSILON) &&
  (y - xyzTest.y < FLOAT_EPSILON) && (y - xyzTest.y > -FLOAT_EPSILON) &&
  (z - xyzTest.z < FLOAT_EPSILON) && (z - xyzTest.z > -FLOAT_EPSILON)
  );
}

template<typename T>
 bool const operator==(const XYZPoint<double> &xyzTest) const
{
 return (
  (x - xyzTest.x < DOUBLE_EPSILON) && (x - xyzTest.x > -DOUBLE_EPSILON) &&
  (y - xyzTest.y < DOUBLE_EPSILON) && (y - xyzTest.y > -DOUBLE_EPSILON) &&
  (z - xyzTest.z < DOUBLE_EPSILON) && (z - xyzTest.z > -DOUBLE_EPSILON)
  );
}

But when I do this
XYZPoint<double> pnt1(1.0,0.0,1.0);
XYZPoint<double> pnt2(1.0,0.0,2.0);

if (pnt1 == pnt2)
{
   ...
}

the specialization for <double> is never called.

Can this be done, and what would be the correct syntax?

Thanks
Mark


I may have stumbled onto the answer.
This syntax is working.

template<typename T>
class XYZPoint
{
    template<typename T>
    bool const operator==(const XYZPoint<T> &xyzTest) const

    bool const operator==(const XYZPoint<float> &xyzTest) const

    bool const operator==(const XYZPoint<double> &xyzTest) const
};

I'm new to templates so I don't understand why (and would like too if
some one can explain). But this works.

Mark

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