Re: Cannot convert from 'Type' to 'const Type&' error with templates

From:
"Igor Tandetnik" <itandetnik@mvps.org>
Newsgroups:
microsoft.public.vc.language
Date:
Mon, 5 Jun 2006 18:00:30 -0400
Message-ID:
<#FDI9wOiGHA.3780@TK2MSFTNGP03.phx.gbl>
Alex Blekhman" <printf("%s@%s.%s", strrev("xfkt"), "yahoo", "com
<printf("%s@%s.%s", strrev("xfkt"), "yahoo", "com");> wrote:

template <
   typename T,
   typename Func,
   typename Pred

compose_t<std::binder2nd<Pred>, Func>
mem_match(
   const T& val,
   Func fn,
   Pred pr = std::equal_to<T>()
)
{
   return compose(std::bind2nd(pr, val), fn);
}

The problem is that mem_match doesn't compile. Compiler
issues error C2783: could not deduce template argument for
'Pred'.

So, now I tried this one:

template <
   typename T,
   typename Func

compose_t<std::binder2nd<std::equal_to<T> >, Func>
mem_match(const T& val, Func fn)
{
   return compose(
       std::bind2nd(
           std::equal_to<T>(), val), fn);
}

This compiles without any problem, however I cannot control
std::equal_to predicate from the outside of mem_match.


Try using both:

template <
    typename T,
    typename Func,
    typename Pred

compose_t<std::binder2nd<Pred>, Func>
mem_match(
    const T& val,
    Func fn,
    Pred pr // note no default value
)
{
    return compose(std::bind2nd(pr, val), fn);
}

template <
    typename T,
    typename Func

compose_t<std::binder2nd<Pred>, Func>
mem_match(const T& val, Func fn)
{
    return mem_match(val, fn, std::equal_to<T>());
}

--
With best wishes,
    Igor Tandetnik

With sufficient thrust, pigs fly just fine. However, this is not
necessarily a good idea. It is hard to be sure where they are going to
land, and it could be dangerous sitting under them as they fly
overhead. -- RFC 1925

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