Re: template function instantiation
George wrote:
Thanks Victor,
The existence of 'g' declaration before the 'f' template is needed
to allow proper parsing of the body of the 'f' function. However,
for all we know it could have been an object (and not a function).
Or it could have been a type. Or a macro that expands into someth
acceptable by the compiler. However, it has NOTHING to do with
the instantiation of 'f'. Instantiation may not even exist, yet
the declaration of 'g' is required -- to allow the definition of
'f' to be compiled.
I think MSVC does not parse f to find whether there is g or what is
g before instantiation, agree?
It would seem so. I don't know for sure since I didn't write MSVC.
What compiler are you using? Your compiler will instantise function f
to int when parsing its definition?
void g(int);
template <class T> void f (T a) { g(a); }
I have no idea whether it will instantiate or not. Unless I use the
function (by calling), how would I know it instantiates it? How do
*you* know the function is instantiated?
Yes, I use VC++ 2005.
V
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