Re: Can you specialize the Template operator==

3DCoderGuy <nobody@nospam.com> wrote:


I assume this is a member function inside something like

template <typename T> class XYZPoint {...};


This is not a specialization of the above, but an overload. The T here
is unrelated to the T which is the class' template parameter. Further,
this overload will never be selected in practice, because in any natural
invocation syntax, T is non-deducible (it doesn't appear anywhere in the
function signature).

Apparently, you want to specialize a member function of class template.
Such a specialization must go outside the class definition, and looks
like this:

template<>
bool const XYZPoint<float>::operator==(const XYZPoint<float>& xyzTest)
const;

--
With best wishes,
    Igor Tandetnik

With sufficient thrust, pigs fly just fine. However, this is not
necessarily a good idea. It is hard to be sure where they are going to
land, and it could be dangerous sitting under them as they fly
overhead. -- RFC 1925