Re: WaitForSingleObject() will not deadlock

From:
Frank Cusack <fcusack@fcusack.com>
Newsgroups:
microsoft.public.vc.mfc
Date:
Mon, 09 Jul 2007 10:08:06 -0700
Message-ID:
<m24pkdpksp.fsf@sucksless.local>
Even with a strictly user-level threads library, the compiler will not
be able to prove that x is not referenced. Unless the thread library
is so simple as to be worthless.

something like

int CreateThread(thread_fn tfn, void *arg)
{
  return (*tfn)(arg);
}

and the thread function (ie, starting point for the new thread) does
not call into opaque functions and does not itself reference x.

-frank

On Sun, 08 Jul 2007 23:03:07 -0400 Joseph M. Newcomer <newcomer@flounder.com> wrote:

Even when x is global, the question is whether or not the function
which is called can modify or use x. Since CreateThread neither
uses nor depends on x, in principle there is no reason the
optimization would be forbidden.
                    joe

On Sat, 07 Jul 2007 13:45:41 -0700, Frank Cusack <fcusack@fcusack.com> wrote:

On Sat, 07 Jul 2007 13:28:58 -0700 Frank Cusack <fcusack@fcusack.com> wrote:

My really last comment!

On Sat, 07 Jul 2007 12:28:50 -0400 Joseph M. Newcomer <newcomer@flounder.com> wrote:

For example

x = 2;
CreateThread()
x = 3;

has the characteristic that there are two sequential assignments of
values to x, and no intervening use of x. Therefore, the compiler
should be free to migrate the assignment of x=3 backward and
eliminate x=2 entirely, or migrate the assignment x=3 forward and
also eliminate x=2 entirely.


No! The compiler is absolutely not allowed to do that. This is not
even a thread thing.


whoops, need to clarify something. If x has scope local to this code
block, yes the compiler can re-order. But in that case, the new thread
cannot see x, period. So we are only talking about global x here.

-frank

Joseph M. Newcomer [MVP]
email: newcomer@flounder.com
Web: http://www.flounder.com
MVP Tips: http://www.flounder.com/mvp_tips.htm

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