Re: A non-const reference may only be bound to an lvalue?

From:
"Carl Daniel [VC++ MVP]" <cpdaniel_remove_this_and_nospam@mvps.org.nospam>
Newsgroups:
microsoft.public.vc.language
Date:
Thu, 13 Dec 2007 22:18:35 -0800
Message-ID:
<uBcwpkhPIHA.5860@TK2MSFTNGP04.phx.gbl>
George wrote:

Hello everyone,

I am debugging MSDN code from,

http://msdn2.microsoft.com/en-us/library/0eestyah(VS.80).aspx

here is my output,

1>main.cpp
1>d:\visual studio 2008\projects\test_c4350\test_c4350\main.cpp(21) :
warning C4350: behavior change: 'B::B(A)' called instead of 'B::B(B
&)' 1> d:\visual studio
2008\projects\test_c4350\test_c4350\main.cpp(13)

see declaration of 'B::B'

1> d:\visual studio
2008\projects\test_c4350\test_c4350\main.cpp(9) : see declaration of
'B::B' 1> A non-const reference may only be bound to an lvalue

I do not quite understand why there is a warning A non-const
reference may only be bound to an lvalue and 'B::B(A)' called instead
of 'B::B(B &)'? Could anyone give some descriptions please?


Class B has two constructors: B::B(B&) and B::B(A), and it also has a
conversion operator B::operator A().

In the example, an object of class 'B' named 'ap' is created and initialized
with the results of a function call that returns an instance of 'B' by
value.

That returned instance of B is not an lvalue - it's a temporary rvalue.

The warning is telling you that under VC++ 7.1 (and later), this results in
this calling sequence:

source()
    A::A() // create the return value for source
    B::B(A) // convert it from an A to a temporary B
B::operator A() // convert that temporary B a temporary A
B::B(A) // initialize ap with that temporary A

.... while under VC7 (and before), the following sequence would have
occurred:

source()
    A::A()
    B::B(A)
B::B(B&) // initialize ap with the temporary instance of B

This change is required by the C++ standard which specifies that a non-const
reference (such as the B& parameter in the B::B(B&) constructor) can only
bind to an lvalue. Since the temporary B that's returned by source() is not
an lvalue, this constructor cannot be used, so the compiler is forced to use
the B::B(A) constructor, which it can use by virtue of B::operator A().

Check out this forum thread, where Tom Widmer gave a good explanation of the
rationale for this rule:

http://www.thescripts.com/forum/thread285370.html

-cd

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