Re: How to bring a dialog itself to top?
How is the thread notifying the window that it needs to be activated?
AliR.
"Evan Li" <music4@tom.com> wrote in message
news:O%23r7feEOJHA.2100@TK2MSFTNGP05.phx.gbl...
AliR,
Thanks for your answer. Unfortunately, it doesn't work. It's behavior is
just same as my original code. My dialog is brought to the top, but it's
not got active.
Evan
"AliR (VC++ MVP)" <AliR@online.nospam> wrote in message
1GkNk.6086$be.3184@nlpi061.nbdc.sbc.com...
Here is the sequence.
void CMyDialog::ActivateMeAndStealFocus()
{
if (IsIconic())
{
ShowWindow(SW_RESTORE);
}
SetForegroundWindow();
BringWindowToTop();
SetActiveWindow();
m_edtCode.SetFocus();
}
AliR.
"Evan Li" <cli4@alcatel-lucent.com> wrote in message
news:OUb33i$NJHA.1396@TK2MSFTNGP05.phx.gbl...
I have a dialog based MFC application. In this app, there is only dialog,
and there is a textbox on the dialog. Also there a thread in this app
that receives data from IP intranet. If the thread receive some message,
then I need the user to input something in the textbox. At that time, I
want to bring the dialog to top and put input focus to the textbox.
I use the folloing code in CMyDialog:
void CMyDialog::BringMeToTop()
{
WINDOWPLACEMENT pl;
pl.length = sizeof(pl);
GetWindowPlacement(&pl);
if (pl.showCmd == SW_SHOWMINIMIZED)
{
pl.showCmd = SW_RESTORE;
SetWindowPlacement(&pl);
}
SetForegroundWindow();
BringWindowToTop();
m_edtCode.SetFocus();
}
But it seems to not work. With this code, the dialog can be brought to
top, but it's not actived, it's title bar is still gray, and the
previous top window's title bar is still blue. So that the text box
cannot get input focus.
By the way, I am working on Win XP.
Any answer will be greatly appreciated.
Evan
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