Re: MFC executable is 100% slower on faster machine

From:
"Alexander Grigoriev" <alegr@earthlink.net>
Newsgroups:
microsoft.public.vc.mfc
Date:
Fri, 22 Jan 2010 21:02:17 -0800
Message-ID:
<uwRS9k#mKHA.2544@TK2MSFTNGP04.phx.gbl>
Do you see much disc activity when you run it? In your new computer, does
the CPU fan spin OK? CPU not overheated?

Note also that when processing large arrays, you want to avoid cache and TLB
thrashing. Better to read the array sequentially than scatter the reads all
over the place.

"Peter Olcott" <NoSpam@SeeScreen.com> wrote in message
news:tY6dnTjgpPqo8MfWnZ2dnUVZ_oWdnZ2d@giganews.com...

I is very memory intensive, thus much faster memory and much larger cache
should make it faster and not slower. It is also single threaded and no
floating point is used at all. I bought the Core i5 specifically because it
has faster access to RAM.

"Alexander Grigoriev" <alegr@earthlink.net> wrote in message
news:%23BWgrp9mKHA.1548@TK2MSFTNGP02.phx.gbl...

Is the application multithreaded? Is it floating-point intensive,
memory-intensive, and what else?

"Peter Olcott" <NoSpam@SeeScreen.com> wrote in message
news:6PydnYAu9qOHgcfWnZ2dnUVZ_v2dnZ2d@giganews.com...

I recently upgraded my computer hardware from a 2.4 Ghz Celeron to a 2.66
Ghz Core i5 and an MFC application that I developed runs only half as
fast on the faster machine. What could be causing this?

Both machines have identical sata hard-drives, and the fast machine has
much faster RAM 1333 ddr3 and 4.0 GB. The slower machine has 2.0 GB of
333 ddr RAM. Why is the slower machine twice as fast on the same
executable?

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