Re: forward declaration & virtual member function return derived class

From:
".rhavin grobert" <clqrq@yahoo.de>
Newsgroups:
comp.lang.c++
Date:
Wed, 2 Jul 2008 11:04:34 -0700 (PDT)
Message-ID:
<228268dc-701d-4be5-9d6b-21a0868370a3@26g2000hsk.googlegroups.com>
On 2 Jul., 19:46, "kep...@gmail.com" <kep...@gmail.com> wrote:

There are 2 abstract base classes:

class IB;
class IA
{
    //...
public:
    virtual IB* GetB() = 0;

}

class IB
{
    //...
public:
    virtual IA* GetA() = 0;

}

Then, this is derived classes:

class CB; //#1
class CA : public IA
{
    //...
public:
    CB* GetB(); //#2}

class CB : public IB
{
    //...
public:
    CA* GetA(); //#3

}

The question is, the declaration do not work.
In C++, the overrided function can return a class which is public
derived from the return type of the function in base class.
When the function #2 returns IB*, it is OK. #3 is OK, too.
But, when #2 returns CB*, the compiler says something like "CB is not
derived from IB".
At #1, I can not declare like this:
class CB : public IB;
The syntax is not passed.

So, what can I do?
There is cycle dependence, but I do not care of the dependence: CA and
CB is almost in a single .cpp file.


you need to give them different names, because you cant overload a
function by just changing it's return-type:

class CB : public IB
{
public:
    CA* _GetA() {return static_cast<CA*>(GetA());};
private:
    IA* GetA();
};

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