Re: forward declaration & virtual member function return derived class

From:
Jonathan Mcdougall <jonathanmcdougall@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 2 Jul 2008 13:35:59 -0700 (PDT)
Message-ID:
<dec5c9d7-553a-435d-aa63-34b0cb4d5a73@d1g2000hsg.googlegroups.com>
On Jul 2, 1:46 pm, "kep...@gmail.com" <kep...@gmail.com> wrote:

There are 2 abstract base classes:

class IB;
class IA
{
    //...
public:
    virtual IB* GetB() = 0;

}

class IB
{
    //...
public:
    virtual IA* GetA() = 0;

}

Then, this is derived classes:

class CB; //#1
class CA : public IA
{
    //...
public:
    CB* GetB(); //#2}

class CB : public IB
{
    //...
public:
    CA* GetA(); //#3

}

The question is, the declaration do not work.


You are missing semicolons at the end of the class definitions. Test
your
code before posting it.

In C++, the overrided function can return a class which is public
derived from the return type of the function in base class.
When the function #2 returns IB*, it is OK. #3 is OK, too.
But, when #2 returns CB*, the compiler says something like "CB is not
derived from IB".
At #1, I can not declare like this:
class CB : public IB;
The syntax is not passed.


As far as I can tell, you cannot use covariance in this case. Either
return a
pointer to the interface or change your design so that you do not have
a
cyclic dependency.

--
Jonathan Mcdougall

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