Re: Serialization

From:
Leigh Johnston <leigh@i42.co.uk>
Newsgroups:
comp.lang.c++
Date:
Thu, 04 Nov 2010 17:53:13 +0000
Message-ID:
<VZ6dnTr85umbbk_RnZ2dnUVZ7qCdnZ2d@giganews.com>
On 04/11/2010 17:28, Andrea Crotti wrote:

I'm doing a very complicated structure for serialize/deserialize
objects, in short I have this abstract class

--8<---------------cut here---------------start------------->8---
#ifndef STREAMABLE_H
#define STREAMABLE_H

#include "Stream.hpp"

template<typename T>
class Serializable
{
public:
     Serializable() {}
     virtual Stream toStream() = 0;
     // used to parse the given stream and create the object
     virtual T parseStream(const Stream&) = 0;
};

#endif /* STREAMABLE_H */
--8<---------------cut here---------------end--------------->8---

and all the objects that want to bea able to create a stream and parse
it have to overload it.

Now 2 problems:
- the definition of the classes is something like
   class PadNodeID : public Serializable<PadNodeID>

   so the template parameter is always the class itself, maybe is it
   possible to avoid it?

- the "parseStream" function doesn't really make sense to be called from
   one object, since it's supposed to create one.
   But making it static and virtual doens't work, so how should I declare
   it in such a way that I can do.

--8<---------------cut here---------------start------------->8---
   Type t = Type::parseStream(st);
--8<---------------cut here---------------end--------------->8---

Thanks again,
Andrea


Why use templates?

class Serializable
{
public:
      Serializable() {}
      virtual Stream toStream() = 0;
      // used to parse the given stream and create the object
      virtual void parseStream(Stream&) = 0;
};

class PadNodeID : public Serializable
{
      PadNodeID(Stream& aStream) { parseStream(aStream); }
      virtual Stream toStream() { ... }
      virtual void parseStream(const Stream&) { ... }
};

int main()
{
      ...
      Stream st;
      PadNodeID node(st);
}

/Leigh

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