Re: returning dynamically allocated object through reference
mundacho@gmail.com wrote:
hello,
I'd like to know if this code is going to create a memory leak in
the calling function (this codes compiles):
ili::IntImg
&RectangleImageComparator::synchronize(const ili::IntImg &pImage)
{
ili::IntImg *tempObj = new ili::IntImg(pImage);
return *tempObj;
}
i wanted to return a reference because it's faster because the
object is not copied but passed directly, isn't it?. My question is
if the calling function will free automatically the object
returned, if I do:
// in the calling function I'd do:
ili::IntImg myVar = synchronize(image); // will myVar be destroyed
automatically???
There are two problems here (or three?).
First, myVar is not a reference so it will make a copy of the returned
value anyway. How much did we save here?
Secondly, there is a simple rule that says that new/delete,
new[]/delete[], and malloc/free always come in pairs. Anything you
allocate, you must also free in a compatible manner. So it is not
automatic.
If you are concerned about execution performance, why do you use new
in the first place. That is surely using more resources than a return
by value.
Bo Persson
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