Re: Semaphore and thread

From:
"Alexander Grigoriev" <alegr@earthlink.net>
Newsgroups:
microsoft.public.vc.language
Date:
Fri, 17 Apr 2009 07:05:58 -0700
Message-ID:
<unSqiW2vJHA.5584@TK2MSFTNGP04.phx.gbl>
Semaphore (as in CreateSemaphore) don't have ownership. A thread can die and
the kernel would not know it acquired semaphore count.

A mutex is owned by a thread. If a thread goes away while holding it, the
mutex will be considered abandoned. But it's very bad design. You must make
sure it doesn't happen.

"Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message
news:gs9umh$ige$1@news.datemas.de...

K2G wrote:

Suppose i have created 2 threads and one semaphore with max resource
count 1.
 T1 is waiting on Semaphore, so resource count is 0 now.
 T2 is also waiting on semaphore . But semaphore is non signled now so
thread is waiting
Now suppose T1 terminates before releasing semaphore,


Uh... You mean, T1 *got* the semaphore (increased its count), and then
ended without releasing the semaphore? Shouldn't the system recognize
that the thread that has the semaphore is now dead and decrease the count
of the semaphore anyway?

Or do you mean T1 is *killed* (by some other thread) before acquiring the
semaphore, while waiting? In that case, shouldn't the wait be terminated
as well?

Is there any way T2 would be able to get the resource ever? Or
resource count of semaphore would be increased anytime?
 If it is mutex then T2 could get resource easily as on termination
wait is abandoned.


V
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