Re: Initialization of local statics

From:
=?ISO-8859-15?Q?Marcel_M=FCller?= <news.5.maazl@spamgourmet.org>
Newsgroups:
comp.lang.c++
Date:
Mon, 27 Sep 2010 00:12:21 +0200
Message-ID:
<4c9fc56b$0$7651$9b4e6d93@newsspool1.arcor-online.net>
Juha Nieminen wrote:

And if so, what
does this mean with respect to threads?


  AFAIK the current standard takes no stance on thread-safety on anything
(I'm not even sure it does so even for malloc()/new, even though in
practical implementations those always are). Hence I don't think the
standard guarantees thread-safety for initializing local statics either.
(In other words, if two threads call the function simultaneously, the
initialization of the static object might get screwed up, unless the
compiler itself guarantees mutual exclusion.)


Just decompiled the binary. You are right, at least gcc 3.3.5 makes
absolutely no protection around the flag.

Maybe because it might be quite expensive, since other threads must be
blocked during the initialization. Of course, the runtime overhead on
each evaluation can be close to zero by using a double check. But we
still need a synchronization resource for each static object. This is
most likely the major drawback.

Marcel

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