Re: 64 bits values or 32 bits

From:
"Paul" <pchristor@yahoo.co.uk>
Newsgroups:
comp.lang.c++
Date:
Fri, 1 Jul 2011 01:01:44 +0100
Message-ID:
<iuj2pc$1smd$1@adenine.netfront.net>
"jim hyden" <netuser501@gmail.com> wrote in message
news:9087354f-58c5-480d-b34a-3543ca5bb93f@l9g2000yqk.googlegroups.com...

Hi,

For the 2 first questions (as comments in the code), the code below is
"half- working" on a 64 bits windows 7 laptop running Windev C++. Is
Windev running in 32 bits mode by default?

Without the if statement in this loop it returns 1 or
-4 294 967 295.

In fact, it is now returning 1 for question 2 which is not what I
expect.

With the if statement, the code returns
2 147 483 648 for 32 loops in question 1 and question 2 when it's 33
loops ?

Something wrong with the algorithm in the code???

while (var_integer > 0)
{
cout << "\n" << nb << "\tvar_int : " << var_integer ;
var_integer *= 2 ;
nb++ ;
if (var_integer > 0)
var_integer2 = var_integer ;
}

/* 1- Compute a n*2 value for 64 iterations */
/* 2- Maximum integer variable iterations for n*2 */
/* 3- Computer the number of iteration needed to reach the value in
question 1 */
int main()
try
{
       long double var_long_double = 1 ;
       long double var_long_double2 = 1 ;
       unsigned int var_integer = 1 ;
       unsigned int var_integer2 = 1 ;
       int i = 1 ;
       int nb = 1 ;
       // QUESTION 1
       while (i < 64)
       {
               var_long_double *= 2 ;
               i++ ;
       }
       cout << "\n1- Value for 64 iteration : " << var_long_double ;
       //QUESTION 2
       while (var_integer > 0)
       {
               cout << "\n" << nb << "\tvar_int : " << var_integer ;
               var_integer *= 2 ;
               nb++ ;
               if (var_integer > 0)
                       var_integer2 = var_integer ;
       }
       cout << "\n\n2- Number as integer variable for " << nb << "
incrementations : " << var_integer2 ;
       // QUESTION 3
       i = 1 ;
       while (var_long_double >= 0)
       {
               var_long_double /= 2 ;
               if (var_long_double >= 0)
                       var_long_double2 = var_long_double ;
               else
                       break ;
               i++ ;
       }
       cout << "\n3-Number of maximum iteration for i as int " << i
<<
"\n" ;
       cout << "\n\n" ;
       system("pause") ;
       return 0 ;
}

catch (runtime_error e)
{
       cout << e.what() << '\n' ;
       keep_window_open("~") ;
}

catch(...)
{
       cout << "Exiting\n" ;
       keep_window_open("~") ;
}


Please excuse me if I am missing the point but can't you just use sizeof to
determine if your varaibles are a different size on a 64-bit implementation?

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