Re: exceptions in destructors

From:
peter koch <peter.koch.larsen@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sat, 15 Aug 2009 12:37:25 CST
Message-ID:
<257e7ee2-9a66-42ec-befa-4cd37b479cdd@26g2000yqk.googlegroups.com>
On 15 Aug., 14:12, Brendan <catph...@catphive.net> wrote:

Oh most venerable and wise clcm! I humbly ask your consideration in
this matter.

g++ let's it pass, but according to the standard, is this program
supposed to call std::terminate? Does it lead to any kind of undefined
behavior?

I thought that having two exceptions active at once was either
supposed to result in a call to std::terminate() even if the exception
is caught as in below, but g++ seems to let it pass. Reference to the
section of the standard appreciated!

Thanks,
Brendan

using std::exception;
using std::cout;
using std::endl;

struct Foo {
   ~Foo() {
     try {
       throw exception();
     } catch (exception e) {
     }
   }

};

int bar() {
   Foo foo();

   throw exception();

}

int main() {
   try {
     bar();
   } catch (exception e) {
   }

   cout << "terminate not called" << endl;

}


That code is perfectly correct. Exceptions in destructors are only
dangerous when they are not caught. Destroying such an object during
stack unwinding processing an exception will cause std::terminate to
be called (and your program to stop).

/Peter

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