Re: exceptions in destructors
Alf P. Steinbach wrote:
* Pete Becker:
Ron wrote:
On Aug 15, 8:12 am, Brendan <catph...@catphive.net> wrote:
Foo foo();
This doesn't create an object. It declares a function called foo
that returns a Foo.
Try it again with:
Foo foo;
Same result, right?
What I actually said, before the misleading snippage, was:
Same result, right? Good catch, though. <g>
I wasn't looking for an explanation of why it was the same. Especially
not this one:
Yes.
The original example was ...
struct Foo {
~Foo() {
try {
throw exception();
} catch (exception e) {
}
}
};
... and as you can see neither the Foo constructor nor its destructor
has any side-effect.
This is quite misleading, since side effects (other than exiting or
throwing exceptions), even if they were present, wouldn't affect the
exception handling in the original example.
--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of
"The Standard C++ Library Extensions: a Tutorial and Reference"
(www.petebecker.com/tr1book)
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