Re: operator < stopped working
All were working well until I decided to add a copy constructor.
Please see the program. I am getting
"c:\Program Files\Microsoft Visual Studio .NET 2003\Vc7\include
\functional(139) : error C2679: binary '<' : no operator found which
takes a right-hand operand of type 'const D' (or there is no
Seems like I can't guarantee constant-ness anymore with the copy
constructor. How do I get around with this ?
// test-sets.cpp : Defines the entry point for the console
using namespace std;
Please drop the semicolons after the function bodies. They are
The usual signature (the compiler-generated one's at least) is
D(D const& d)
There is also a need to have a const version of that function:
std::string const& getA() const
Don't let it throw you off that they have the same body, they are
bool operator < (D d) const
The usual (idiomatic) way is to pass the operand by a reference
bool operator < (D const& d) const
typedef std::set<D> dsets;
D *d = new D();
What you should write is
Or at least
Drop the habit of doing "new" all the time. Besides, you're
inconsistent. You didn't 'new' your 'dsets' object!
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