Re: NRVO or I think so

From:
"Igor Tandetnik" <itandetnik@mvps.org>
Newsgroups:
microsoft.public.vc.language
Date:
Fri, 13 Mar 2009 10:04:15 -0400
Message-ID:
<#10QcS#oJHA.5980@TK2MSFTNGP06.phx.gbl>
"K?r?at" <kursattheking@gmail.com> wrote in message
news:OfmcnA8oJHA.5100@TK2MSFTNGP03.phx.gbl

I expeced this output :

Constructor... (For line 3)
Copy constructor... (For line 7, a temporary object is
copy-constructed from foo_1)
Destructor... (For foo_1)
Copy constructor... (For line 12, foo is copy-constructed from the
temporary object)
Destructor... (for foo)
Destructor... (for the temporary object)

but the real output is (using Visual Studio 2008 compiler with debug
configuration) :

Constructor...
Copy constructor...
Destructor...
Destructor...

When I checked the assemby out I see address of the foo pushed into
the stack and used directly in getFoo () rather than creating a new
temporary. This is the optimization named NRVO, isn't this?


No. NRVO would have eliminated the last remaining
copy-constructor/destructor pair, by having foo_1 be an alias for the
space reserved for return value.
--
With best wishes,
    Igor Tandetnik

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