Re: // how can I access A::a?

From:

Francis Glassborow <francis.glassborow@btinternet.com>

Newsgroups:

comp.lang.c++.moderated

Date:

Wed, 13 Apr 2011 15:04:06 CST

Message-ID:

<zNCdnXxq15Sb_DjQnZ2dnUVZ8uWdnZ2d@bt.com>

On 13/04/2011 09:01, dick wrote:

         /* multi_level_inheritance.cpp */
         struct A
         {
             int a;
         };

         struct B1 : public A
         {
             int a;
         };

         struct B2 : public A
         {
             int a;
         };

         struct C : public B1, public B2
         {
             int a;
         };

         int main()
         {
             C ccc;

             ccc.a=123;

             ccc.B1::a=456;

/* 0030 */ ccc.B1::A::a=789;

         }

// c++ multi_level_inheritance.cpp
// multi_level_inheritance.cpp: In function int main():
// multi_level_inheritance.cpp:30: error: A is an ambiguous base of C

// how can I access A::a?

Leaving aside the horrible nature of such code, you can do it via an
intermediate reference:

replace the critical line with:

/* 0030 */ B1 & bbb(ccc);
             bbb.A::a = 789;

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