Re: What is the correct way to derive a class in regard to overloaded operators
olanglois@sympatico.ca wrote:
I am trying to derive a new class that will add new functions but no
new data members and the base class has overloaded operators
(+,-,+=,-=,etc...) returning either (Base &) or (const Base) depending
on the operator:
class Derived : public Base
{
};
The problem occurs if I do the following
Derived d1,d2;
Derived d3 = d1+d2;
what should be the better approach?
Just add
Derived(const Base&) and
Derived &operator=(const Base&)
If 'Derived' never has to know that addition, etc., is being performed,
then yes, it should be sufficient.
or should it be better to redeclare all the operators (there is a lot
of them) in the derived class and perform nothing except calling the
base class version and return Derived reference or object.
I don't think how it could help _unless_ you're foreseeing the need for
'Derived' to amend the operation somehow in the future (even if it does
not need it now). Introduction of an interface should be done sooner
rather than later.
V
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